Question

C6H12O6 = 2C2H5OH + 2CO2 de acuerdo a la estequemetria de esta reacción si tenemos 1000 g de glucosa (C6H12O6) ¿Cuantos gramos se producirán de etanol (C2H5OH) y de dióxido de carbono (CO2)?(Incluya formulas, masas molares y cálculos)

Answer 1

Mm C2H5OH = 46 g/mol

CO2 = 44 g/mol

C6H12O6 = 180 g/mol

gC2H5OH=1000 gC6H12O6 x 1 molC6H12O6 x 2 molC2H5OHx46 g C2H5OH

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180 g C6H12O6 1 mol C6H12O6 1 mol C2H5OH

g = 511 de alcohol

g CO2=1000 g C6H12O6 x 1 molC6H12O6 x 2 molCO2 x 44 g CO2

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180 g C6H12O6 1 mol C6H12O6 1 mol CO2

g = 488.88 de CO2