Question

que masa de magnesio se necesita para que reaccione con 9.27 g de nitrógeno? de acuerdo a la siguiente ecuación Mg+ N2 → Mg3 N2

Gracias...

Answer 1

3Mg + N2 → Mg3N2

Mm N2 = 28 g/mol

Mg = 24 g/mol

g Mg = 9.27 g N2 x 1 mol N2 x 3 mol Mg x 24 g Mg

```````````````` ``````````````````` ``````````````````

28 g N2 1 mol N2 1 mol Mg

g = 23.84 de Mg