Question

hola necesito ayuda urgente con esta tarea de matematica
log (3x - 1) -log ( 2 x +3 ) = x - log 25
3 + log x = log 57 - log 19
log x + log 36 = log 612
2 log (x - 3) = log x - log 4

porfavoooooor es urgente
es mi examen final
porfavoooooor

Answer 1

Respuesta:

1) log (3x - 1) -log ( 2 x +3 ) = logx - log 25

Log(3x-1/2x-3) = log(x/25)

aplicando potencia 10:

3x-1/2x-3 = x/25

75x-25/2x-3=x

75x-25= 2x²-3x

2x²-78x+25=0

x1= 38.67; x2= 0.32

2) 3 + log x = log 57 - log 19

Log(10³)+Log(x) = Log(57)-Log(19)

Log(10³X) = Log(57/19)

10³X=57/19

X= 3/10³

X= 0.003

3) log x + log 36 = log 612

Log(x*36) = Log612

x*36=612

x= 17

4) 2 log (x - 3) = log x - log 4

Log(x-3)²= Log(x/4)

(x-3)²=(x/4)

x²-6x+9=x/4

4x²-24x+36=x

4x²-25x+36=0

x1= 4; x2= 9/4