Question

1 resuelva usando productos notables

a) (3x+1)^2=

b) (2a+3b)^2=

c) (x-2)(x+3)=

d) (2a-5)(2a+5)=

e) (a+2) ^3=

F) (4x+5)^3=

Answer 1

a) (3x+1)^2 = (3x)^2 + 2(3x)(1) + 1^2 = 9x^2 + 6x + 1

b) (2a+3b)^2 = (2a)^2 + 2(2a)(3b) + (3b)^2 = 4a^2 + 12ab + 9b^2}

c) (x-2)(x+3) = x^2 + 3x - 2x - 6 = x^2 + x - 6

d) (2a-5)(2a+5) = (2a)^2 - 5^2 = 4a^2 - 25

e) (a+2)^3 = a^3 + 3(a)^2(2) + 3(a)(2)^2 + 2^3 = a^3 + 6a^2 + 12a + 8

f) (4x+5)^3 = (4x)^3 + 3(4x)^2(5) + 3(4x)(5)^2 + 5^3 = 64x^3 + 60x^2 + 300x + 125