Question

dado el valor del perimetro de cada figura, halla la medida de cada lado:
ayuda!!!

Answer 1

A. Es un Triángulo Equilátero cuyo Perímetro mide 69 cm.

69 = 2(3x-2) + (2x +1)

69 = 6x – 4 + 2x + 1

69 = 8x -3

69 + 3 = 8x

72 = 8x

X = 72/8 = 9

X = 9

Los lados miden:

L1 = L2 = 3X - 2

L1 = L2 = 3(9) – 2 = 27 - 2 = 25 cm

L3 = 2x + 1

L3 = 2(9) + 1 = 18 + 1 = 19 cm

B. Este es un Paralelogramo con perímetro de 36 cm; con L1 = 4x + 5; L2 = 4x – 2; L3 = 3x -2 y L4 = 9x - 5

36 = (4x + 5) + (4x - 2) + (3x - 2) + (9x - 5)

36 = 4x + 5 + 4x – 2 + 3x – 2 + 9x – 5

36 = 20x - 4

36 + 4 = 20x

40 = 20x

X = 40/20 = 2

X = 2

Entonces las longitudes de las aristas.

L1 = 4x + 5 = 4(2) + 5 = 20 + 5 = 25 cm

L2 = 4x – 2 = 4(2) – 2 = 8 - 2 = 6 cm

L3 = 3x – 2 = 3(2) – 2 = 6 – 2 = 4 cm

L4 = 9x – 5 = 9(2) – 5 = 18 – 2 = 5 = 13 cm

C. La tercera figura tiene un perímetro de 36 cm con aristas L1 = 2x + 7; L2 = x + 2; L3 = x + 1; L4 = x + 4 y L5 = L2 + L3

36 = (2x + 7) + (x + 2) + (x +1) + (x + 4) + [(x + 2) + (x + 1)]

36 = 2x + 7 + x + 2 + x + 1 + x + 4 + x + 2 + x + 1

36 = 7x + 17

36 – 17 = 7x

19 = 7x

X = 19/7 = 2,7142 cm

L1 = 2(2,7142) + 7 = 12,4284 cm

L2 = (2,7142) +2 = 4, 7142 cm

L3 = (2,7142) + 1 = 3,7142 cm

L4 = (2,7142) + 4 = 6,7142 cm

L5 = L2 + L3 = 4,7142 + 3,7142 = 8,4284 cm

Answer 2

Respuesta:

que buena idea gracias