Question

Ayuda facil con algebra

Answer 1

Sea a>b

a² + b² = 4ab ║ (a+b)²=a²+b²+2ab -----> a²+b²=(a+b)²-2ab

Reemplazamos

(a+b)²-2ab=4ab

(a+b)² = 6ab

√(a+b)² = √6ab

| a+b | = √6ab ║ a > b

a+b = √6ab

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a² + b² = 4ab ║ (a-b)²=a²+b²-2ab -----> a²+b² = (a-b)²+2ab

Reemplazamos

(a-b)²+2ab = 4ab

(a-b)² = 2ab

√(a-b)² = √2ab

| a-b | =√2ab ║ a>b ----> a-b > 0

a-b = √2ab

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CALCULAR :

(a+b)/(a-b) = (√6ab)/(√2ab) -----> √3 >> Respuesta

espero se entienda xD

SALUDOS!!