Question

(8a^3b^4-2/7a^4b^3)+(-5a^4b^3-1/3a^3b^4)

Answer 1

$= (8 {a}^{3} {b}^{4} - \frac{2}{7} {a}^{4} {b}^{3} ) + ( - 5 {a}^{4} {b}^{3} - \frac{1}{3} {a}^{3} {b}^{4} ) \\ = (8 {a}^{3} {b}^{4} - \frac{1}{3} {a}^{3} {b}^{4} ) + (- \frac{2}{7} {a}^{4} {b}^{3} - 5 {a}^{4} {b}^{3} ) \\ = \frac{24{a}^{3} {b}^{4} - {a}^{3} {b}^{4} }{3} + \frac{ - 2{a}^{4} {b}^{3} - 35{a}^{4} {b}^{3} }{7} \\ = \frac{23{a}^{3} {b}^{4}}{3} - \frac{37{a}^{4} {b}^{3}}{7}$