Respuestas
14) Resolver los siguientes sistemas :
a) 3x - y + 5z = 2
-7y + z = 7
2z =0
2z =0
z = 0/2
z = 0
-7y + 0 = 7
y = 7/-7
y =- 1
3x - y + 5z = 2
3x -(- 1) + 5 *0 = 2
3x = 2 -1
x = 1/3
Solución : x = 1 /3 y = - 1 z = 0
b ) x + 3y - 2z = 4
3x + 2y + z = 7
4x + 4y + 2z = 0
( 3x + 2y + z = 7 ) * 2
6x + 4y + 2z = 14
x + 3y - 2z = 4 +
_______________
7x + 7y = 18
( 3x + 2y + z = 7 ) * -2
-6x - 4y - 2z = -14
4x + 4y + 2z =0 +
___________________
-2x = -14
x = -14/-2
x = 7
7x+ 7y =18
7*7 + 7y = 18
7y = 18 -49
7y = -31
y = -31/7
4x + 4y + 2z = 0
4 * 7 + 4 *( -31/7) + 2z =0
28 - 124 / 7 + 2Z =0
2Z = -72/7
Z = -72/7/2
z = -36/7
La solución es :
x = 7 y = -31/7 z = - 36/7