Question

determina el valor numerico de las siguientes expresiones algebraicas sabiendo que x=-2 y=3yz=4 .

Answer 1

x= - 2, y = 3, z = 4
A). 3x^2y-2xy^2 =
3 (-2)^2 * (3) - 2(-2)(3^2) = 3*4*3 + 2*2*9 = 36 + 36 = 72 

B). -1/2x^3y^2+3x^2z^2
[-1/2](-2)^3 (3)^2 + 3(-2)^2 (4^2) = (-1/2)*(-8)(9) + 3(4)(16) = 36 + 192 = 228

C). x^2 (y-2)-y (x+2)+3y^3
(-2)^2 (3 - 2) - (3) (-2+2) + 3(3)^2 = 4(1) -3(0) + 27 = 4 -0 +27 = 31

D). 2/3 x^3y^2z-5x^2y^3z^2+10
(2/3) (-2)^3 (3)^2 (4) - 5(-2)^2 (3)^3 (4)^2 + 10 = (2/3)(-8)(9)(4) - 5(4)(9)(16)+10 = -192 - 2880 + 10 = -3062

E).3/4 xy^2z^3 - x^2y^3z^2+ x^3y^2z^3-1/2
(3/4)(-2)(3^2)(4^3) - (-2)^2 (3^3)(4^2) + (-2)^3 (3)^2 (4^3) - 1/2 = -864 - 1728 - 4608 - 1/2 = - 7200 - 1/2 = - 14401/2

Answer 2

Respuesta:

Lo que debes hacer es susituir los valores de las variables en cada expresión:

x= - 2, y = 3, z = 4

A). 3x^2y-2xy^2 =

3 (-2)^2 * (3) - 2(-2)(3^2) = 3*4*3 + 2*2*9 = 36 + 36 = 72

B). -1/2x^3y^2+3x^2z^2

[-1/2](-2)^3 (3)^2 + 3(-2)^2 (4^2) = (-1/2)*(-8)(9) + 3(4)(16) = 36 + 192 = 228

C). x^2 (y-2)-y (x+2)+3y^3

(-2)^2 (3 - 2) - (3) (-2+2) + 3(3)^2 = 4(1) -3(0) + 27 = 4 -0 +27 = 31

D). 2/3 x^3y^2z-5x^2y^3z^2+10

(2/3) (-2)^3 (3)^2 (4) - 5(-2)^2 (3)^3 (4)^2 + 10 = (2/3)(-8)(9)(4) - 5(4)(9)(16)+10 = -192 - 2880 + 10 = -3062

E).3/4 xy^2z^3 - x^2y^3z^2+ x^3y^2z^3-1/2

(3/4)(-2)(3^2)(4^3) - (-2)^2 (3^3)(4^2) + (-2)^3 (3)^2 (4^3) - 1/2 = -864 - 1728 - 4608 - 1/2 = - 7200 - 1/2 = - 14401/2

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