Question

En la reacción: Na2CO3 + Ba (OH)2 NaOH + BaCO3
¿Cuantas moles de hidróxido de sodio se producen al reaccionar 250 g de carbonato de sodio?
¿Cuántas moles de hidróxido de bario se consumen?
¿Cuántos g de carbonato de bario se producen?

Answer 1

                          Na2CO3 + Ba(OH)2 →  2NaOH + BaCO3
Mm NaOH = 40 g/mol   Ba(OH)2 = 171.34 g/mol   Na2CO3 = 106 g/mol     BaCO3 = 197 g/mol     CaCO3 = 100 g/mol

a) mol NaOH = 250 g Na2CO3 x  1 mol Na2CO3  x  2 mol NaOH                                                      ````````````````````      ````````````````````                                                     106 g Na2CO3      1 mol Na2CO3
mol NaOH =  4.71

b) mol Ba(OH)2 = 250 g Na2CO3 x  1 mol Na2CO3  x  1 mol Ba(OH)2                                                         ````````````````````      ````````````````````                                                         106 g Na2CO3      1 mol Na2CO3
mol Ba(OH)2 = 2.35
                                     
c) 
g BaCO3=250 g Na2CO3 x 1 mol Na2CO3 x  1 mol BaCO3   x 197 g BaCO3                                              ```````````````````    ````````````````````    ``````````````````
                                            106 g Na2CO3      1 mol Na2CO3  1 mol BaCO3
g BaCO3 = 464.62