Question

Me podrian ayudar porfavor ??

Answer 1

a) x=3
b x=8
c)x=11
d) a=1
e) x=2/5

supongo que estas son las respuestas...

Answer 2

a.

$5 {x}^{2} = 45 \\ {x}^{2} = \frac{45}{5} \\ {x}^{2} = 9 \\ x = + - 3$

b.

${x}^{2} - 56 = x \\ {x}^{2} - x - 56 = 0 \\ (x - 8)(x + 7) = 0 \\ x = 8 \\ x = - 7$

c.

$7 {x}^{2} + 14 = 861 \\ 7 {x}^{2} = 861 - 14 \\ 7 {x}^{2} = 847 \\ {x}^{2} = 121 \\ x = + - 11$

d.

$\frac{ {a}^{2} }{3} + \frac{5}{6} = \frac{11}{12} \\ \frac{ {a}^{2} }{3} = \frac{11}{12} - \frac{5}{6} \\ \frac{ {a}^{2} }{3} = \frac{1}{6} \\ {a}^{2} = \frac{1}{2} \\ a = + - \frac{1}{ \sqrt{2} }$

e.

$- 25 {x}^{2} + 4 = 0 \\ - 25 {x}^{2} = - 4 \\ 25 {x}^{2} = 4 \\ {x}^{2} = \frac{4}{25} \\ x = + - \sqrt{ \frac{4}{25} } \\ x = + - \frac{2}{5}$