Question

-x^6+x^4-2x^2-1 . -x^2-3x^6

Answer 1

(-x^6 + x^4 -2x^2 -1) (-x^2  -3x^6 )=
-x^2(-x^6 + x^4 - 2x^2 - 1) -  3x^6(-x^6 + x^4 - 2x^2 - 1)=
x^8 - x^6 +2x^4 +x^2  +3x^12 - 3x^10 +6x^8  +3x^6=

3x^12 - 3x^10 + 7x^8 +2x^6 +2x^4 +x^2

Answer 2

$( {x}^{6} + {x}^{4} - 2 {x}^{2} - 1)( - {x}^{2} - 3 {x}^{6} ) \\ - {x}^{8} - {3x}^{12} - {x}^{6} - 3 {x}^{10} + 2 {x}^{4} + 6 {x}^{8} + {x}^{2} + 3 {x}^{6} \\ - 3 {x}^{12} - 3 {x}^{10} + 5 {x}^{8} + 2 {x}^{6} + {x}^{4} + {x}^{2}$
y esto se puede factorizar

$- 3 {x}^{12} - 3 {x}^{10} + 5 {x}^{8} + 2 {x}^{6} + {x}^{4} + {x}^{2} \\ {x}^{2} ( - 3 {x}^{10} - 3 {x}^{8} + 5 {x}^{6} + 2 {x}^{4} + {x}^{2} + 1)$