Question

Sean:a=2,b=-3, c=-5, d=8 si se reemplazan estos valores en la operación. ayudenme porfavor
-(2b+c)+3(-4a+d)=
(3c+b)+3(-2a+d)=
-(-4b+c)+3(-3a+d)=

Answer 1

a=2,b=-3, c=-5, d=8

1)  -(2b+c)+3(-4a+d)=
-(2(-3)-5)+3(-4(2)+8)=
11

2)  (3c+b)+3(-2a+d)=
(3(-5)-3)+3(-2(2)+8)=
-18+12=
-6

3)  -(-4b+c)+3(-3a+d)=
-(-4(-2)-5)+3(-3(2)+8)=
-(3)+3(2)=
3

Answer 2

- ( 2bc ) + 3 ( -4a + d )
= - (2(-3)(-5)) + 3(-4(2) + 8 )
= - 30 + 3 ( -8 + 8 )
= - 30 + 3 (0)
= - 30 + 0
= -30

(3c+b)+3(-2a+d)
= ( 3(-5) + (-3)) + 3 (-2(2) + 8 )
= ( -15 - 3 ) + 3 ( -4 + 8 )
= ( -18 ) + 3 ( 4 )
= -18 + 12
= - 6

-(-4b+c)+3(-3a+d)
= - ( 4(-3) + (-5) ) + 3 ( -3(2) + 8)
= - ( -12 - 5 ) + 3 ( -6 + 8 )
= - (-17 ) + 3 ( -6 + 8 )
= 17 + 3 (2)
= 17 + 6
= 23