Question

Cuantos gramos de oxido de hierro Fe203 se pueden producir a partir de 2.50 g de oxigeno que reacccionan con hierro solido?

Answer 1

                 4 Fe + 3O2 → 2Fe2O3
Mm Fe2O3 = 159.68 g/mol             O2 = 32  g/mol
g Fe2O3 = 2.50 g O2 x 1 mol O2  x  2 mol Fe2O3 x 159.68 g Fe2O3                                      ````````````    ````````````````````   ``````````````````````                                       32 g O2          3 mol O2         1 mol Fe2O3
g Fe2O3 = 8.32