Question

Si A=2AL CUBOX3 A LA QUINTAX5AL CUADRADO B= 2x3A LA SEPTIMAx5 A LA QUINTA

Determinar el valos de:
minimo comun multiplo(A;B) / MAXIMO COMUN DIVISOR(A;B)

Answer 1

$A=2^{3}x 3 ^{5}x5 ^{2}$
$B=2x 3^{7}x 5^{5}$
MCM(A,B)=$2^{3}x 3^{7}x 5^{5}$÷
MCD(A,B)=$2x 3^{5} x 5^{2}$
=2²x3²x5³