Question

Demuestra siguiente identidad trigonométrica
cot B + Sen B/(1+cosB)= cscB

Answer 1

El ejercicio se resuelve de esta manera

Answer 2

$cot \beta + \frac{sen \beta }{1+cos \beta } = csc \beta$

$\frac{cos \beta }{sen \beta } + \frac{sen \beta }{1+cos \beta } = csc \beta$

$\frac{cos \beta (1+cos \beta )+sen \beta (sen \beta )}{sen \beta (1+cos \beta )} = csc \beta$

$\frac{ cos \beta +cos \beta ^{2} +sen \beta ^{2} }{sen \beta (1+cos \beta )} = csc \beta$

$\frac{cos \beta +1}{sen \beta (cos \beta +1)} = csc \beta$

$\frac{1}{sen \beta } = csc \beta$

$csc \beta = csc \beta$