Question

ayuda con esto ,es de trigonometría

Answer 1

Lv,
Un esbozo del sistema va a yudar a visualizar mejor
                           A
                            |                                     AB = cable = ??
                            |                                     AC = altura antena
                            |                                     CB = 40 m
                            |                                     
                            |_________                 Angulo ABC = 52° 20'
                           C                  B
                        En el triangulo rectángulo ACB, en relación al angulo ABC

                                                          CB = cateto adyacente
                                                          AB = hipotenusa
                        Podemos usar función coseno
                                               cos ABC = CB/AB
                                                AB = CB/(cos ABC)
                       Con los datos disponibles
                                                 AB = 40/(cos 52° 20')
                                                               20' = 20/60 = 0.333°...
                                                  AB = 40/(cos 52.333°)
                                                                       cos 52.333° = 0.6117
                                                  AB = 40/(0.6117)
                                                   AB = 65.4588
           longitud aproximada cable = 65 m (aproximación por defecto)