Question

ayudm con este deber ..

Answer 1

$a)\ \dfrac{ \frac{7}{2}+ \frac{3}{5}-\frac{1}{2} }{ (\frac{8}{3}- \frac{1}{5}) ( \frac{8}{3}- \frac{1}{7}) }= \\ \\ Primero \ resolvemos \ los \ parentesis \\ \\ \\ \dfrac{ \frac{7}{2}+ \frac{3}{5}-\frac{1}{2} }{ (\frac{40}{15}- \frac{3}{15}) ( \frac{56}{21}- \frac{3}{21}) }= \dfrac{ \frac{7}{2}+ \frac{3}{5}-\frac{1}{2} }{ (\frac{37}{15}) ( \frac{53}{21}) }= \dfrac{ \frac{7}{2}+ \frac{3}{5}-\frac{1}{2} }{ \frac{1961}{315} }= \\ \\ \\ resolvemos \ el \ numerador$

$\dfrac{ \frac{35}{10}+ \frac{6}{10}-\frac{5}{10} }{ \frac{1961}{315} }= \dfrac{ \frac{36}{10} }{ \frac{1961}{315} }= \\ \\ Realizamos\ la \ division \\ \\ \dfrac{36}{10}: \dfrac{1961}{315} = \boxed{ \frac{1134}{1961}}$


$b)\ \dfrac{ \frac{4}{5} * \frac{3}{2}* \frac{1}{2}}{ (\frac{7}{2}-\frac{3}{5}+ \frac{2}{3}) * 7 }= \\ \\ Resolvemos \ las \ multiplicaciones \ del \ numerador \\ \\ \\ \dfrac{ \frac{12}{20} }{ (\frac{7}{2}-\frac{3}{5}+ \frac{2}{3}) * 7 }= \\ \\ Resolvemos \ la \ resta \ y \ la \ suma \ del \ denominador \\ \\ \\ \dfrac{ \frac{12}{20} }{ (\frac{105}{30}-\frac{18}{30}+ \frac{20}{30}) * 7 }= \dfrac{ \frac{12}{20} }{ \frac{107}{30}*7} = \dfrac{ \frac{12}{20} }{ \frac{749}{30}}=$

$\dfrac{ \frac{12}{20} }{ \frac{749}{30}}= \frac{12*30}{20*749}= \boxed{ \frac{18}{749}}$


Espero que te sirva, salu2!!!!