Question

Porfavor ayudenme con ese ejercicio.

Answer 1

x + 1/x = 4/√3
(x² + 1)/x = 4/√3
x² + 1= 4/√3 × x
(x² + 1) × √3 = 4x
√3x² - 4x + √3 = 0

(-(-4) +-√((-4)² -  4√3×√3))/2√3
(4 +-√(16 -  4√3²))/2√3
(4 +-√(16 -  4 × 3))/2√3
(4 +-√(16 -  12))/2√3
(4 +-√4)/2√3
(4 +-2)/2√3
(4 + 2)/2√3
6/2√3  ⇒  3/√3   ⇒ 3√3/3  ⇒ √3
x₁ = √3

(4 - 2)/2√3
2/2√3  ⇒   1/√3  ⇒ √3/3
x₂ = √3/3