Question

6/8-{4/7+[(3/4+1/2)-3/8+4/6)]}

Answer 1

6/8-{4/7+[(3/4+1/2)-3/8+4/6)]}


$\frac{6}{8}-\left\{\frac{4}{7}+\left[\left(\frac{3}{4}+\frac{1}{2}\right)-\frac{3}{8}+\frac{4}{6}\right]\right\}$

$\frac{6}{8}-\left(\frac{4}{7}+\frac{3}{4}+\frac{1}{2}-\frac{3}{8}+\frac{4}{6}\right)$

* $\frac{6}{8}=\frac{3}{4}$

* $\frac{4}{6}:\quad \frac{2}{3}$

$\frac{3}{4}- \frac{4\cdot \:24}{168}+\frac{3\cdot \:42}{168}+\frac{1\cdot \:84}{168}-\frac{3\cdot \:21}{168}+\frac{2\cdot \:56}{168}$

$\frac{3}{4} - \frac{4\cdot \:24+3\cdot \:42+1\cdot \:84-3\cdot \:21+2\cdot \:56}{168}$

$\frac{3}{4}-\frac{355}{168}$

$\frac{3\cdot \:42}{168}-\frac{355}{168}$

$\frac{-229}{168}$

$-\frac{229}{168}$