Question

log2x-log(4x+3)=1. ecuaciones exponencial ¡ayuda!

Answer 1

Log 2x - log(4x+3) = 1

Log (2x/(4x+3))= 1

2x /(4x+3) = 10^1

2x = 10(4x+3)

2x = 40x +30

-30= 40x - 2x

-30 = 38x

X = - 30/38

X = - 15/19