Question

factorizar 20y²+5y-11

Answer 1

20y²+5y-11=0

y=-b+-√(b²-4ac)/2a=-5+-√(5²+4*20*11)/40= 
hacemos operaciones y nos da:
y1=5/8

y2=7/8

(y-5/8) (y+7/8)