Question

se disuelven 25 gr de CaCO3 en 900 ml de solucion. determine su molaridad ??? pls

Answer 1

Mm CaCO3 = 100 g/mol
1.  calcular moles
n = m/Mm
n = 25 g / 100 g/mol
n = 0.25 mol
2. convertir mL a L
L = 900 / 1000 = 0.900 L
3. Calcular M = n/V(L)
M = 0.25 mol / 0.900 L
M = 0.27 molar