Question

Ayuda!!! Sistemas de ecuaciones.

Answer 1

           x/9 = y/12 = z/6             (I)             2x - 3y - 5z = 4             (II)
De (I)                  y = 12x/9 = 4x/3     (III)
                  z = 6x/9 = 2x/3        (IV)
(III) y (IV) en (II)                              2x - 3(4x/3) - 5(2x/3) = 4
Efectuando
                               2x - 4x - (10/3)x = 4
multiplicando todo por 3
                               6x - 12x - 10x = 12

                               - 16x = 12

                                 x = 12/(- 16)
                                                                     x = - 3/4

 x en (II) y (IV)         
                                    y = 4(- 3/4)/3
                                                                        y = - 1

                                    z = 2(- 3/4(/3
                                                                        z = - 1/2
         Solución
                            x = - 3/4
                            y = - 1
                            z = - 1/2

                                                             no dejes de comprobar!!