Question

reducir a una sola fracción

Answer 1

$e.- 2x+5-\frac{25}{1-2x}=\frac{-4x^2-8x-20}{-2x+1} Pasos 2x+5-\frac{25}{1-2x} =\frac{2x}{1}+\frac{5}{1}-\frac{25}{-2x+1} =\frac{2x\left(-2x+1\right)}{-2x+1}+\frac{5\left(-2x+1\right)}{-2x+1}-\frac{25}{-2x+1} =\frac{2x\left(-2x+1\right)+5\left(-2x+1\right)-25}{-2x+1} =\frac{-4x^2-8x-20}{-2x+1} g.-\frac{\left(\frac{5x^2+15x}{2x+6}\right)}{\left(1+\frac{5}{2x}\right)} = \frac{5x^2}{2x+5} Pasos =\frac{5xx}{2x+5} 5xx=5x^{2} =\frac{5x^2}{2x+5}$