Question

HCL+Zn ---->ZnCl2+H2. Si reacciona 10 g de Zn con la suficiente cantidad de acido .Calcular cuantos gramos de cloruro de Zinc se forma

Answer 1

                     2 HCl  +  Zn →  ZnCl2 + H2

Mm Zn = 65.38 g/mol
  ZnCl2 = 136.28 g/mol

g ZnCl2 = 10 g Zn  x  1 mol Zn  x  1 mol ZnCl2  x 136.28 g ZnCl2
                                  `````````````    ```````````````````   ````````````````````
                                  65.38 g Zn      1 mol Zn          1 mol ZnCl2

g ZnCl2 = 20.84