Question

me podrian ayudar a resolver este ejecisio metodo de dos incognitas suma y resta
7×+3y=2
6×+5y=9

Answer 1

7x + 3y = 2
6x + 5y = 9
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x = (2-3y)/7
6x + 5y = 9
---------------------
6·(2-3y)/7 + 5y = 9
(12-18y)/7 + 5y = 9
12-18y + 35y = 63
17y = 51
y = 51/17
y = 3
----------------------
7x + 3y = 2
7x + 3 · 3 = 2
7x + 9 = 2
7x = -7
x = -7/7
x = -1

Answer 2

ejem:
x-6=2
lo que esta en un lado restando pasas sumando
x=2+6    x=8
7x+3y=2
7x/7+3y=2
x+3y=2/7
x+y=0.3/3
xy=0.1
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6x+5y=9
6x/6+5y/5=9
x+y=(9/6=1.5     y 1.5/3=0.5
xy=0.5