Question

C6H12O6 = 2C2H5OH + 2CO2 ¿ cuantos moles de alcohol etilico se producen apartir de 12.5 moles de azucar de uva ?

Answer 1

                         C6H12O6  → 2C2H5OH + 2CO2

n C2H5OH = 12.5 mol C6H12O6  x  2 mol C2H5OH
                                                         ``````````````````````
                                                         1 mol C6H12O6

n C2H5OH = 25 moles