Question

Un recipiente de 3L contiene 0.2mol de Nitrogeno a 190°C. ¿Cuál será su presión? a) 2.53atm. b) 3.53atm. c)4.53atm d)5.53atm

Answer 1

aplicar Ley de los Gases Ideales
V x P = n x R x T
V = 3 L
T = 190 ºC + 273 = 463 K
R = 0.0821 (L atm / mol K)
n = 0.2 mol
calcular P = ?
P = 0.2 atm  x  0.0821 (L atm/ mol K) x 463 K     ``````````````````````````````````````````````````````````                                3 L
P = 2.53 atm  (respuesta: a)