Question

Me ayudan a resolver esto porfaaa

Recuerda las reglas para asignar números de oxidación a los elementos que forman un compuesto observan los ejemplos resueltos y escribe el número pero no siguientes compuestos aplicando las reglas respectivas


Li2O
NaNo3
HBr
CH4
HCIO
H3PO4
KL
Ba(OH)2
KMnO4
Al2O3
ZnO
Sn
TiO2
Fe2O3
H2CO3
K2Cr2O7
HIO3
HgO
Fe
RbBrO3


Es para mañana ayuda!!!

Answer 1

r+1 -2
Li2 O                    Li: +1  O: -2
``````````
+2 -2 = 0

+1 +x -2
Na N O3                   Na: +1, N: +5; O: -2
``````````````
+1+x-6 = 0
     x = 6 - 1 = +5

+1 -1
H  Br                             H: +1       Br: -1
`````````````
+1-1 = 0

+x +1
C  H4               C: -4; H: +1
```````````
+x + 4 = 0
    x = - 4

+1 +x -2 
H  CI  O                       H: +1;  Cl: +1; O: -2
`````````````````
+1+x- 2 = 0
         x = +2 -1 = +1

+1 +x -2
H3 P O4                H: +1;  P: +3: O: -2
```````````````
+3+x-8 = 0
      x = +8 -3 = +5

+1 -1
 K   I                   K: +1;  I: -1
``````````
+1-1=0

+2  -2  +1
Ba ( O H)2
```````````````````
+2 -4 +2 = 0

 +1 +x  -2
 K  Mn O4                  K: +1; Mn: +7; O: -2
````````````````
+1 +x -8 = 0
       x = +8 -1
       x = +7

+3 -2 = 0
Al2O3

+2-2 = 0
Zn O

 0
Sn         esta libre y sin combinarse

+x-2
Ti O2              Tu: +4  O: -2
``````````
+x -4 = 0
  x = +4

+3  -2
Fe2O3              Fe: +3
````````````
+6 -6 = 0

+1 +x -2
H2 C O3                      H: +1; C: +4; O: -2
```````````````
+2+x-6 = 0
      x = +6 -2
      x = +4

+1 +x  -2
K2 Cr2 O7                  K: +1;  Cr: +6;  O: -2
```````````````````
+2 +2x - 14 = 0
        2x = 14 - 2
          x = 12/2
           x = +6

+1+x  -2
  H  I  O 3                      H: +1;   I: +5:  O: -2
``````````````````
+1 +x -6 = 0
       x = +6 -1
        x = +5

+2 -2 = 0
Hg O
 
0
Fe

+1 +x -2
Rb Br O3                   Rb: +1;  Br: +5;  O: -2
`````````````````
+1 +x - 6 =
      x = +6 -1
       x = +5