Question

si
$\sqrt{37 + x = 1 + \sqrt{ \times } }$
entonces
$\sqrt{2 \sqrt{ \times } } =$
¿???

Answer 1

$\sqrt{37+x}$= 1 + $\sqrt{x}$
37 + x = $(1 + \sqrt{x})^{2}$
37 + x = $1 + 2 \sqrt{x} + x$
$36 = 2 \sqrt{x}$

Entonces:
$\sqrt{2 \sqrt{x}}$ 
$\sqrt{36}$
6