Question

Logaritmos

log(x-1)+ log x= log 10

5log(subindice 2) 4+ log(subindice 2) 8= log 2x

Answer 1

$log(x - 1) + log(x) = log(10) \\ log(x(x - 1)) = log(10) \\ x(x - 1) = 10 \\ {x}^{2} - x - 10 = 0$
Ocupando la formula de la cuadratica:
$\frac{ - ( - 1) + \sqrt{ {( - 1)}^{2} - 4 \times 1 \times ( - 10)} }{2 \times 1} \\ = \frac{1 + \sqrt{1 + 40} }{2} \\ = \frac{1 + \sqrt{41} }{2}$