Question

Encuentra 4 soluciones diferentes a las ecuaciones x4-16=0

Answer 1

sea:
$(x^{2})^{2} - 4^{2} = 0 \\ (x^{2} + 4)(x^{2}-4) = 0 \\ (x- \sqrt{-4} )(x+ \sqrt{-4} )(x+2)(x-2) = 0 \\ x = \sqrt{-4} , x = -\sqrt{-4}, x=2,x=-2 \\ x = (\sqrt{-4},-\sqrt{-4},-2,2})$