Question

Hallar (fog) y (gof)

Answer 1

$f(x) = \sqrt{(3 - x)} \\ g(x) = \sqrt{( {x}^{2} - 1) } \\ (fog)(x) = f(g(x)) = f( \sqrt{ {x}^{2} - 1} ) \\ = \sqrt{3 - \sqrt{ {x}^{2} - 1 } } \\ (gof)(x) = g(f(x)) \\ g( \sqrt{3 - x} ) = \sqrt{ {( \sqrt{3 - x} )}^{2} - 1 } = \\ \sqrt{3 - x - 1} = \sqrt{2 - x}$

Answer 2

Explicacion

f(x) = ✔3 - x

g(x) = ✔x^2 - 1

fog(x) = f(g(x))

fog(x) = f( ✔x^2 - 1 )

fog(x) = ✔3 - ✔x^2 - 1