Question

¿Alguien lo podría resolver?, por favor

8{2-[q+2(q-3)]+1]=3-(8-3q)

Answer 1

$8(2 - (9 + 2(q - 3)) + 1) = 3 - (8 - 39) \\ = 8(2 - (9 + 2q - 6) + 1) = 3 - ( - 31) \\ = 8(2 - (3 + 2q) + 1) = 3 + 31 \\ = 8(2 - 3 - 2q + 1) = 34 \\ = 8(0 - 2q) = 34 \\ = 8 \times ( - 2q) = 34 \\ = - 16q = 34 \\ = - 16q \div ( - 16) = 34 \div ( - 16) \\ = q = - \frac{34}{16} \\ = q = - \frac{17}{8}$