Asignatura: Matemáticas
Autor: valengatita
hace 9 años

10 ejercicios resueltos de operaciones combinadas con numeros racionales

Respuestas

Respuesta dada por: Bagg

Vamos a plantear cada operación y a resolver paso a paso cada operación.

(3 – 8/4) + [15 – (-2/3)]

$(3 -8/4) + [15 -(-\frac{2}{3}) ]=\\(3-2)+[15+\frac{2}{3}]=\\1+[\frac{15*3+2}{3*1}]=\\ 1+\frac{47}{3}=\\\frac{1*3+47}{3*1}=\\\frac{50}{3}$

5 - [63/2 - 2 - (12 – 8) - 4/3 + 6]

$5 - [\frac{63}{2} - 2 - (12 - 8) - \frac{4}{3} + 6]=\\5-[\frac{63-2*2}{2*1} -(4)+\frac{-4*1+6*3}{3}]=\\5-[\frac{59}{2}-4+\frac{14}{3}]=\\5-[\frac{59*3}{6} -\frac{24}{6} +\frac{28}{6}]\\5-[\frac{177-24+28}{6} ]\\5-[\frac{181}{6}]\\ \frac{5*6-181*1}{6*1}=\\\frac{30-181}{6}=\\\frac{-151}{6}$

18 / [12 / (-2)]

$18 / [12 / (-2)]=\\18/[-6]=\\-3$

2/5*(5 +3.2/ 6 - 4). (4 /2 - 3 + 6)

$\frac{2}{5} *(5 +3*\frac{2}{6} - 4)*(\frac{4}{2} - 3 + 6)=\\\frac{2}{5} *(5 +\frac{6}{6} - 4)*(2 - 3 + 6)=\\\frac{2}{5} *(5 +1- 4)*(5)=\\\frac{2}{5} *(2)*(5)=\\\frac{2*2*5}{5}=\\4$

(5/4 - 6/4 + 2/4) * (2/6-5/2)

$(5/4 - 7/4 + 1/4) * (2/6-5/2)=\\(\frac{5-7+1}{4} ) * (\frac{2*2-5*6}{2*6} )=\\(\frac{-1}{4} ) * (\frac{-26}{12} )=\\(\frac{-1}{4} ) * (\frac{-13}{6} )=\\\frac{-1*(-13)}{4*6}=\\\frac{13}{24}$

(-12)* 3 + 18 /(-12 / 6 + 8)

$(-12)* 3 + 18 /(\frac{-12}{6} + 8)=\\-36 + 18 /(-2 + 8)=\\-36+\frac{-18}{6} =\\-36-3=\\-39$

6* {3* [-9 + 4/(5*3 - 9)] - 3*(40/10 - 8)}

$6* [3* [-9 + 4/(5*3 - 9)] - 3*(40/10 - 8)]=\\6* [3* [-9 + 4/(15 - 9)] - 3*(4 - 8)]=\\6* [3* [-9 + 4/6] - 3*4]=\\6* [3* [-9 + \frac{2}{3} ] - 12]=\\6* [3* [\frac{-9*3+2}{3} ] - 12]=\\6* [3* [\frac{-25}{3} ] - 12]=\\6* [\frac{3*(-25)}{3} - 12]=\\6* [ -25- 12]=\\6*-37=\\-222$

(1/3 – 5/4) + [3/5 – (2/3)]

$(\frac{1}{3} -\frac{5}{4} ) + [\frac{3}{5} - \frac{2}{3} ]=\\(\frac{3*4-5*3}{3*4}) + [\frac{3*3-2*5}{5*3}]=\\(\frac{-3}{12}) + [\frac{-1}{15}]=\\(\frac{-1}{4}) + [\frac{-1}{15}]=\\(\frac{-1*15-4*1}{4*15})=\\\frac{-19}{60}$