Question

Reduce a la forma normal la ecuacion 12x-5y+8=0

Answer 1

Forma normal de la recta

$\frac{a}{ \sqrt{a^2+b^2} } x+ \frac{b}{ \sqrt{a^2+b^2} } y+ \frac{c}{ \sqrt{a^2+b^2} }=0$

12x - 5y + 8 =0

$\sqrt{a^2+b^2} = \sqrt{12^2+(-5)^2} =13$

Ecuación normal

$\frac{12}{13} x- \frac{5}{13} y+ \frac{8}{13} =0$