Question

(2√243-5√363+3√48+4√108-3√147+7√75)/√3

Answer 1

(2√243-5√363+3√48+4√108-3√147+7√75)/√3

$\frac{\left(2\sqrt{243}-5\sqrt{363}+3\sqrt{48}+4\sqrt{108}-3\sqrt{147}+7\sqrt{75}\right)}{\sqrt{3}}$

$2\sqrt{243}=2\cdot \:9\sqrt{3}=18\sqrt{3}$

$5\sqrt{363}=5\cdot \:11\sqrt{3}=55\sqrt{3}$

$3\sqrt{48}=3\cdot \:4\sqrt{3}=12\sqrt{3}$

$4\sqrt{108}= 4\cdot \:6\sqrt{3}=24\sqrt{3}$

$3\sqrt{147}= 3\cdot \:7\sqrt{3}=21\sqrt{3}$

$7\sqrt{75}=5\cdot \:7\sqrt{3}=35\sqrt{3}$

$\frac{18\sqrt{3}-55\sqrt{3}+12\sqrt{3}+24\sqrt{3}-21\sqrt{3}+35\sqrt{3}}{\sqrt{3}}$

$\frac{13\sqrt{3}}{\sqrt{3}}$

$13$

RESPUESTA : 13