Question

Analizar las siguientes ecuaciones lineales o de primer grado para determinar su solución...

1.- 6(6a-3)+4a=5a+52

2.- 4d+2(10-d)=50

3.- 9c+4c-2= 4c+3c+16

4.- 3.2b+4.5b+3-2=-1.3b+5b-7

5.- e-5+3e=-6e+1-2(3e-5)

6.- 5(3f-4)-5f+12=20-3(4f-5+2f)

7.- 3(4g-2)+6-6g=2g-3(3g-6)-8

8.- 5(2h-3)-13=3h-2(3h-5)+1

Answer 1

Hola amiga, Buenas Tardes:

1.- 6(6a-3)+4a=5a+52

6×6a= 36a, 6×3= 18, +4

36a-18+4a

36a+4a, -18

40a-18 = 5a+52

40a-5a=52+18

35a = 70

a = 70÷2
a=2

2.- 4d+2(10-d)=50

4d+(20-2d)=50

4d-2d+20=50

2d+20=50

2d = 50-30

2d = 30

d = 30÷2
d = 15

3.- 9c+4c-2=4c+3c+16

13c-2 = 7c+16

13c-7c = 2+16

6c = 18

c = 18÷6
c = 3

4.- 3.2b+4.5b+3-2=-1.3b+5b-7

7.7b+1 = 3.7b-7

7.7-3.7 = -7-1

4b = -8

b = -8÷4
b= -2


5.- e-5+3e=-6e+1-2(3e-5) "no se puede resolver"

6.- 5(3f-4)-5f+12=20-3(4f-5+2f)

10f-8=20-3(4f-52f)

10f-8 = 20+144f

10f-144f = 20+8

-134f = 28

f = -(14÷67)
f = -0.20895522...

7.- 3(4g-2)+6-6g=2g-3(3g-6)-8

12g-6+6-6g = 2g-3(3g-6)-8

6g = 2g-3(3g-6)-8

6g = -7g+10

6g+7g = 10

13g = 10

g = 10÷13
g = 0.76923976...


8.- 5(2h-3)-13=3h-2(3h-5)+1

3h-2(3h-5)+1 = 5(2h-3)-13

-3h+11 = 5(2h-3)-13

-3h+11 = 10h-28

-13h+11 = -28

-13h = -39

h = -(36÷13)
h = 3