Question

Molaridad de 30 gr de ca(oh)2 en 900ml de solucion

Answer 1

Mm Ca(OH)2 = 74 g/mol

1. calcular moles

n = masa/Mm

n = 30 g / 74 g/mol

n = 0.405 moles

2. convertir mL a L

L = 900 / 1000 = 0.900 L

3. calcular la Molaridad = moles soluto / V(L)

M = 0.405 moles / 0.900 L

M = 0.45 molar