Respuestas
Respuesta dada por:
2
Resolución:
=====================<<✪✪✪>>
Sea la ecuación de primer grado:
x + 1 + 2x = 50
3x = 50 - 1
3x = 49
x = 49/3
x = 16,33...
=====================<<✪✪✪>>
Sea la ecuación de primer grado:
x + 1 + 2x = 50
3x = 50 - 1
3x = 49
x = 49/3
x = 16,33...
Respuesta dada por:
2
- Resolvemos la ecuación:
![x + 1 + 2x = 50 x + 1 + 2x = 50](https://tex.z-dn.net/?f=x+%2B+1+%2B+2x+%3D+50+)
![3x = 50 - 1 3x = 50 - 1](https://tex.z-dn.net/?f=3x+%3D+50+-+1+)
![3x = 49 3x = 49](https://tex.z-dn.net/?f=3x+%3D+49+)
![x = \frac{49}{3} x = \frac{49}{3}](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7B49%7D%7B3%7D+)
- Comprobamos:
![x + 1 + 2x = 50 x + 1 + 2x = 50](https://tex.z-dn.net/?f=x+%2B+1+%2B+2x+%3D+50+)
![\frac{49}{3} + 1 + 2 . \frac{49}{3} = 50 \frac{49}{3} + 1 + 2 . \frac{49}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B49%7D%7B3%7D++%2B+1+%2B+2+.++%5Cfrac%7B49%7D%7B3%7D+%3D+50)
![\frac{49}{3} + \frac{1}{1} + \frac{2}{1} . \frac{49}{3} = 50 \frac{49}{3} + \frac{1}{1} + \frac{2}{1} . \frac{49}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B49%7D%7B3%7D+%2B++%5Cfrac%7B1%7D%7B1%7D+%2B++%5Cfrac%7B2%7D%7B1%7D+.++%5Cfrac%7B49%7D%7B3%7D+%3D+50)
![\frac{49}{3} + \frac{1}{1} + \frac{2.49}{1.3} = 50 \frac{49}{3} + \frac{1}{1} + \frac{2.49}{1.3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B49%7D%7B3%7D+%2B++%5Cfrac%7B1%7D%7B1%7D+%2B++%5Cfrac%7B2.49%7D%7B1.3%7D+%3D+50+)
![\frac{49}{3} + \frac{1}{1} + \frac{98}{3} = 50 \frac{49}{3} + \frac{1}{1} + \frac{98}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B49%7D%7B3%7D+%2B++%5Cfrac%7B1%7D%7B1%7D+%2B++%5Cfrac%7B98%7D%7B3%7D+%3D+50+)
![\frac{3:3.49+3:1.1+3:3.98}{3} = 50 \frac{3:3.49+3:1.1+3:3.98}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B3%3A3.49%2B3%3A1.1%2B3%3A3.98%7D%7B3%7D+%3D+50+)
![\frac{49+3+98}{3} = 50 \frac{49+3+98}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B49%2B3%2B98%7D%7B3%7D+%3D+50+)
![\frac{150}{3} = 50 \frac{150}{3} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B150%7D%7B3%7D+%3D+50+)
![\frac{50}{1} = 50 \frac{50}{1} = 50](https://tex.z-dn.net/?f=+%5Cfrac%7B50%7D%7B1%7D+%3D+50+)
![50 = 50 50 = 50](https://tex.z-dn.net/?f=50+%3D+50+)
- Comprobamos:
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