Question

POR FAVOR
Siendo P(×) = Q(×) Hallar el valor de "a" y "b"
P(×)= x'3 + ( 2a-b) x'2 +3
Q(×)= 5x'3 + (a-1) x'2 +3

Answer 1

[(-5X'3-3)/X'2]+1=a
X'3+{2[(-5X'3-3)/X'2]+1}-b}X'2+3=0
-{[(-X'3-3)/X'2]-2[(-5X'3-3)/X'2]+1}=b
X'3+{2[(-5X'3-3)/X'2]+1}+{[(-X'3-3)/X'2]-2[(-5X'3-3)/X'2]+1}}/x'2+3=0
X=3,018
a= -0,782
b= 0,732