Question

por favor hallar el valor de x doy 20 ptos

Answer 1

Esos son triángulos notables. El primero es un triángulo de 60° y 30° (si te dan 60, se supone que el segundo es 30°), y este triángulo dice que el cateto frente al 60 mide k$\sqrt{3}$, el que está frente al 30 mide k, y la hipotenusa 2k. Hallaremos el valor de k:
2k = $\sqrt{3}$
k= $\frac{ \sqrt{3} }{2}$.
Reemplazamos:
x= k$\sqrt{3}$ = $\frac{ \sqrt{3}}{2} \sqrt{3} = \frac{3}{2}$
y= k = $\frac{ \sqrt{3} }{2}$
2°: El triángulo de 45 dice que los catetos miden k, y la hipotenusa k$\sqrt{2}$.
Vemos que k=$\sqrt{7}$, entonces:
x= k=$\sqrt{7}$
y= $\sqrt{7}$ x $\sqrt{2}$ = $\sqrt{14}$
3°: Es el mismo triángulo de 60 y 30, solo que ahora da el 30. La hipotenusa vale 2k, aquí es igual a $10\sqrt{3}$, entonces k= $5\sqrt{3}$.
x= k = $5\sqrt{3}$
y= k$\sqrt{3}$ = $5\sqrt{3}$ x $\sqrt{3}$ = 5 x 3 = 15
Es pero que te sirva. Saludos!

Answer 2

Respuesta:

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