Question

ayuda urgente!!!!!!!!

$( \sqrt{16} - \sqrt{4} ) \times {2}^{4} + {4}^{33} \div {4}^{31} =$

Answer 1

RESOLVER

$\left(\sqrt{16}-\sqrt{4}\right)\cdot 2^4+4^{33}\div 4^{31}$
$\left(\sqrt{16}-\sqrt{4}\right)\cdot \:2^4=2^5$
$\frac{4^{33}}{4^{31}}=4^2$
$2^5+4^2 48$

RESPUESTA : 48