Question

16x- 3x-(6-9x) =30x+ (3x+2)-(x+3)

Answer 1

16x-[3x-(6-9x)]=30x+[-(3x+2)-(x+3)]

16x-[3x-6+9x]=30x+[-3x-2-x-3]

16x-[12x-6]=30x+[-4x-5]

16x-12x+6 = 30x-4x-5

4x + 6 = 26x - 5

6+5 = 26x - 4x

11 = 22x

11/22 = x

1/2 = x 
Si no estoy mal