Question

P(x)=(x+3)2+5x Hallar: P(0)+P(1)+P(–2)

Answer 1

P(0)=(0+3)2+5(0) = (3)2+0 = 6
P(1)=(1+3)2+5(1) = (4)2+5 = 13
P(-2)=(-2+3)2+5(-2)=(-1)2+(-10) = -2-10=-12

6+13-12=7