Question

calcula
√√625;(√5)^2 ;(√12/7)^4;√√16

Answer 1

Resolver:
√√625 =²*²√625 =⁴√625  como 625 = 5 *5*5*5 = 5⁴  Tenemos
⁴√625 = ⁴√5⁴ = 5⁴/⁴= 5
Solucion:
√√625 = 5

(√5)² = (5)²/² = 5
Soolucion:
(√5)² = 5

(√12/7)⁴ =
(12/7)⁴/² =
(12/7)² =
12²/7² =
144/49
Solucion:
(√12/7)⁴ = 144/49

√√16 =  Como 16 = 2*2*2*2 = 2⁴
⁴√2⁴ = 2⁴/⁴ = 2

Solucion:
√√16= 2

Answer 2

$Propiedad \ ra \acute{i}z \ de \ ra \acute{i}z \\ \\ \sqrt{ \sqrt{625}} =\sqrt{ \sqrt{5^4}} = \sqrt[2*2]{5^4}= \sqrt[4]{5^{4} } = 5 \\ \\ ( \sqrt{5})^{2} = 5 \\ \\ \sqrt{ (\frac{12}{7})^{4}}= ( \frac{12}{7}) ^{2}= \frac{144}{49} \\ \\ \sqrt{ \sqrt{16}}= \sqrt{ \sqrt{2^{4}}} = \sqrt[4]{2^{4}} =2$

Espero que te sirva, salu2!!!!