Respuestas
Respuesta dada por:
2
a.)
![{0,001= \frac{1}{1000}}\\\\{\log \left(\frac{1}{1000}\right)=x}\\\\{10^{\log \left(\frac{1}{1000}\right)} =10^x}\\\\{\frac{1}{1000}=10^x}\\\\{10^{-3}=10^x}\\\\{x=-3} {0,001= \frac{1}{1000}}\\\\{\log \left(\frac{1}{1000}\right)=x}\\\\{10^{\log \left(\frac{1}{1000}\right)} =10^x}\\\\{\frac{1}{1000}=10^x}\\\\{10^{-3}=10^x}\\\\{x=-3}](https://tex.z-dn.net/?f=%7B0%2C001%3D+%5Cfrac%7B1%7D%7B1000%7D%7D%5C%5C%5C%5C%7B%5Clog+%5Cleft%28%5Cfrac%7B1%7D%7B1000%7D%5Cright%29%3Dx%7D%5C%5C%5C%5C%7B10%5E%7B%5Clog+%5Cleft%28%5Cfrac%7B1%7D%7B1000%7D%5Cright%29%7D+%3D10%5Ex%7D%5C%5C%5C%5C%7B%5Cfrac%7B1%7D%7B1000%7D%3D10%5Ex%7D%5C%5C%5C%5C%7B10%5E%7B-3%7D%3D10%5Ex%7D%5C%5C%5C%5C%7Bx%3D-3%7D)
b.)
![{\log _9 (3) =x} \\\\{9^{\log_9 (3) }=9^x}\\\\{3=9^x}\\\\{3 = 3^{2x}}\\\\{2x=1}\\\\{x=1/2} {\log _9 (3) =x} \\\\{9^{\log_9 (3) }=9^x}\\\\{3=9^x}\\\\{3 = 3^{2x}}\\\\{2x=1}\\\\{x=1/2}](https://tex.z-dn.net/?f=%7B%5Clog+_9+%283%29+%3Dx%7D+%5C%5C%5C%5C%7B9%5E%7B%5Clog_9+%283%29+%7D%3D9%5Ex%7D%5C%5C%5C%5C%7B3%3D9%5Ex%7D%5C%5C%5C%5C%7B3+%3D+3%5E%7B2x%7D%7D%5C%5C%5C%5C%7B2x%3D1%7D%5C%5C%5C%5C%7Bx%3D1%2F2%7D)
c.)
![{\log_{\frac{1}{4} } (2) = x}\\\\\\{\dfrac{1}{4}^{\log_{\frac{1}{4}}(2)}= \dfrac{1}{4}^x}\\\\\\{2= 2^{-2x}}\\\\{x=-\frac{1}{2}} {\log_{\frac{1}{4} } (2) = x}\\\\\\{\dfrac{1}{4}^{\log_{\frac{1}{4}}(2)}= \dfrac{1}{4}^x}\\\\\\{2= 2^{-2x}}\\\\{x=-\frac{1}{2}}](https://tex.z-dn.net/?f=%7B%5Clog_%7B%5Cfrac%7B1%7D%7B4%7D+%7D+%282%29+%3D+x%7D%5C%5C%5C%5C%5C%5C%7B%5Cdfrac%7B1%7D%7B4%7D%5E%7B%5Clog_%7B%5Cfrac%7B1%7D%7B4%7D%7D%282%29%7D%3D+%5Cdfrac%7B1%7D%7B4%7D%5Ex%7D%5C%5C%5C%5C%5C%5C%7B2%3D+2%5E%7B-2x%7D%7D%5C%5C%5C%5C%7Bx%3D-%5Cfrac%7B1%7D%7B2%7D%7D)
d.)
![{\log_2 (2)=x}\\\\{2^{\log_2 (2)} =2^x}\\\\{2 = 2^x}\\\\{x=1} {\log_2 (2)=x}\\\\{2^{\log_2 (2)} =2^x}\\\\{2 = 2^x}\\\\{x=1}](https://tex.z-dn.net/?f=%7B%5Clog_2+%282%29%3Dx%7D%5C%5C%5C%5C%7B2%5E%7B%5Clog_2+%282%29%7D+%3D2%5Ex%7D%5C%5C%5C%5C%7B2+%3D+2%5Ex%7D%5C%5C%5C%5C%7Bx%3D1%7D)
Salu2. :)
b.)
c.)
d.)
Salu2. :)
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