Cual es el radio,diametro y perimetro de
area= 313cm²
area=1253m²
area= 61243m²
me pueden ayudar por favor
Respuestas
Respuesta dada por:
1
Cuál es el radio,diámetro y perímetro de
1) área= 313 cm²
2) área=1253 m²
3) área= 61243 m²
me pueden ayudar por favor
![1) \'area= \pi radio^2 \\ \\ 313\ cm^2= \pi radio^2 \\ \\ 313\ cm^2= (3,14) radio^2 \\ \\ \dfrac{313\ cm^2}{3,14}= radio^2 \\ \\ 99,68\ cm^2= radio^2 \\ \\ \sqrt{99,68\ cm^2}= radio\qquad\to \boxed{radio= 9,98\ cm} \\ \\ Radio = 9,98\ cm \quad Diametro = 2radio \quad \to Diametro = 2*9,98\ cm \\ \boxed{Diametro = 19,96\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(9,98\ cm) \qquad \to \boxed{Perimetro =62,67\ cm} 1) \'area= \pi radio^2 \\ \\ 313\ cm^2= \pi radio^2 \\ \\ 313\ cm^2= (3,14) radio^2 \\ \\ \dfrac{313\ cm^2}{3,14}= radio^2 \\ \\ 99,68\ cm^2= radio^2 \\ \\ \sqrt{99,68\ cm^2}= radio\qquad\to \boxed{radio= 9,98\ cm} \\ \\ Radio = 9,98\ cm \quad Diametro = 2radio \quad \to Diametro = 2*9,98\ cm \\ \boxed{Diametro = 19,96\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(9,98\ cm) \qquad \to \boxed{Perimetro =62,67\ cm}](https://tex.z-dn.net/?f=1%29+%5C%27area%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C++313%5C+cm%5E2%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C++313%5C+cm%5E2%3D+%283%2C14%29+radio%5E2+%5C%5C++%5C%5C+++%5Cdfrac%7B313%5C+cm%5E2%7D%7B3%2C14%7D%3D+radio%5E2+%5C%5C++%5C%5C+99%2C68%5C+cm%5E2%3D+radio%5E2++%5C%5C++%5C%5C++%5Csqrt%7B99%2C68%5C+cm%5E2%7D%3D+radio%5Cqquad%5Cto++%5Cboxed%7Bradio%3D+9%2C98%5C+cm%7D+%5C%5C++%5C%5C+Radio+%3D+9%2C98%5C+cm+%5Cquad+Diametro+%3D+2radio+%5Cquad+%5Cto+Diametro+%3D+2%2A9%2C98%5C+cm+%5C%5C++%5Cboxed%7BDiametro+%3D+19%2C96%5C+cm%7D+%5C%5C++%5C%5C+Perimetro+%3D+2%2A+%5Cpi+%2A+radio++%5C%5C++%5C%5C+Perimetro+%3D+2%2A%283%2C14%29%2A%289%2C98%5C+cm%29+%5Cqquad+%5Cto++%5Cboxed%7BPerimetro+%3D62%2C67%5C+cm%7D++++)
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![2) \'area= \pi radio^2 \\ \\ 1253\ cm^2= \pi radio^2 \\ \\ 1253\ cm^2= (3,14) radio^2 \\ \\ \dfrac{1253\ cm^2}{3,14}= radio^2 \\ \\ 399,04\ cm^2= radio^2 \\ \\ \sqrt{399,04\ cm^2}= radio\qquad\to \boxed{radio=19,98\ cm} \\ \\ Radio = 19,98\ cm \quad Diametro = 2radio \ \to Diametro = 2*19,98\ cm \\ \boxed{Diametro = 39,96\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(39,96\ cm) \qquad \to \boxed{Perimetro =250,95 \ cm} 2) \'area= \pi radio^2 \\ \\ 1253\ cm^2= \pi radio^2 \\ \\ 1253\ cm^2= (3,14) radio^2 \\ \\ \dfrac{1253\ cm^2}{3,14}= radio^2 \\ \\ 399,04\ cm^2= radio^2 \\ \\ \sqrt{399,04\ cm^2}= radio\qquad\to \boxed{radio=19,98\ cm} \\ \\ Radio = 19,98\ cm \quad Diametro = 2radio \ \to Diametro = 2*19,98\ cm \\ \boxed{Diametro = 39,96\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(39,96\ cm) \qquad \to \boxed{Perimetro =250,95 \ cm}](https://tex.z-dn.net/?f=2%29+%5C%27area%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C++1253%5C+cm%5E2%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C++1253%5C+cm%5E2%3D+%283%2C14%29+radio%5E2+%5C%5C++%5C%5C+++%5Cdfrac%7B1253%5C+cm%5E2%7D%7B3%2C14%7D%3D+radio%5E2+%5C%5C++%5C%5C+399%2C04%5C+cm%5E2%3D+radio%5E2++%5C%5C++%5C%5C++%5Csqrt%7B399%2C04%5C+cm%5E2%7D%3D+radio%5Cqquad%5Cto++%5Cboxed%7Bradio%3D19%2C98%5C+cm%7D+%5C%5C++%5C%5C+Radio+%3D+19%2C98%5C+cm+%5Cquad+Diametro+%3D+2radio+%5C+%5Cto+Diametro+%3D+2%2A19%2C98%5C+cm+%5C%5C++%5Cboxed%7BDiametro+%3D+39%2C96%5C+cm%7D+%5C%5C++%5C%5C+Perimetro+%3D+2%2A+%5Cpi+%2A+radio++%5C%5C++%5C%5C+Perimetro+%3D+2%2A%283%2C14%29%2A%2839%2C96%5C+cm%29+%5Cqquad+%5Cto++%5Cboxed%7BPerimetro+%3D250%2C95+%5C+cm%7D++)
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![3) \'area= \pi radio^2 \\ \\ 61243\ cm^2= \pi radio^2 \\ \\ 61243\ cm^2= (3,14) radio^2 \\ \\ \dfrac{61243\ cm^2}{3,14}= radio^2 \\ \\19504,14\ cm^2= radio^2 \\ \\ \sqrt{19504,14\ cm^2}= radio\qquad\to \boxed{radio= 139,66\ cm} \\ \\ Radio =139,66\ cm\quad \to Diametro = 2*139,66\ cm \\ \boxed{Diametro =279, 32\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(139,66\ cm) \quad \to \boxed{Perimetro =877,06\ cm} 3) \'area= \pi radio^2 \\ \\ 61243\ cm^2= \pi radio^2 \\ \\ 61243\ cm^2= (3,14) radio^2 \\ \\ \dfrac{61243\ cm^2}{3,14}= radio^2 \\ \\19504,14\ cm^2= radio^2 \\ \\ \sqrt{19504,14\ cm^2}= radio\qquad\to \boxed{radio= 139,66\ cm} \\ \\ Radio =139,66\ cm\quad \to Diametro = 2*139,66\ cm \\ \boxed{Diametro =279, 32\ cm} \\ \\ Perimetro = 2* \pi * radio \\ \\ Perimetro = 2*(3,14)*(139,66\ cm) \quad \to \boxed{Perimetro =877,06\ cm}](https://tex.z-dn.net/?f=3%29+%5C%27area%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C++61243%5C+cm%5E2%3D++%5Cpi+radio%5E2+%5C%5C++%5C%5C+61243%5C+cm%5E2%3D+%283%2C14%29+radio%5E2+%5C%5C++%5C%5C+++%5Cdfrac%7B61243%5C+cm%5E2%7D%7B3%2C14%7D%3D+radio%5E2+%5C%5C++%5C%5C19504%2C14%5C+cm%5E2%3D+radio%5E2++%5C%5C++%5C%5C++%5Csqrt%7B19504%2C14%5C+cm%5E2%7D%3D+radio%5Cqquad%5Cto++%5Cboxed%7Bradio%3D+139%2C66%5C+cm%7D+%5C%5C++%5C%5C+Radio+%3D139%2C66%5C+cm%5Cquad+%5Cto+Diametro+%3D+2%2A139%2C66%5C+cm+%5C%5C++%5Cboxed%7BDiametro+%3D279%2C+32%5C+cm%7D+%5C%5C++%5C%5C+Perimetro+%3D+2%2A+%5Cpi+%2A+radio++%5C%5C++%5C%5C+Perimetro+%3D+2%2A%283%2C14%29%2A%28139%2C66%5C+cm%29+%5Cquad+%5Cto++%5Cboxed%7BPerimetro+%3D877%2C06%5C+cm%7D++)
Espero que te sirva, salu2!!!!
1) área= 313 cm²
2) área=1253 m²
3) área= 61243 m²
me pueden ayudar por favor
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Espero que te sirva, salu2!!!!
marthasocorro7:
muchas gracias
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