Question

Me podrías ayudar con este sistema de ecuación: (se puede resolver por el método que quieras)

x+1      y-1
------ + ------ = 0
3           2

x+2y       x+y+2
-------- - ----------- = 0
3                4

Answer 1

Respuesta:

(x + 1) / 3 + (y - 1) / 2 = 0
(x + 2y) / 3 - (x + y + 2) / 4 = 0

(x + 1) / 3 + (y - 1) / 2 = 0
(2(x + 1) + 3(y - 1)) / 6 = 0
2(x + 1) + 3(y - 1) = 0
2x + 2 + 3y - 3 = 0
2x + 3y - 1 = 0
2x + 3y = 1

(x + 2y) / 3 - (x + y + 2) / 4 = 0
(4(x + 2y) - 3(x + y + 2)) / 12 = 0
4(x + 2y) - 3(x + y + 2) = 0
4x + 8y - 3x - 3y - 6 = 0
x + 5y - 6 = 0
x + 5y = 6

2x + 3y = 1
x + 5y = 6

2x + 3y = 1
2(x) + 2(5y) = 2(6)

2x + 3y = 1
2x + 10y = 12

2x + 10y = 12
- 2x - 3y = - 1
--------------------
         7y = 11

7y = 11
y = 11 / 7

x + 5y = 6
x + 5(11 / 7) = 6
x + 55 / 7 = 6
x = 6 - 55 / 7
x = (42 - 55) / 7
x = - 13 / 7

x = - 13 / 7
y = 11 / 7

Answer 2

Veamos :

(x+1)/3 + ( y-1) /2 =0
(x+1)/3 = -( y-1)/2
2(x+1) = 3 ( -y+1)
2x+2 = -3y +3
2x= -3y +1
x = (-3y +1 ) /2

Hallamos la otra "x" :

(x+2y)/3 - (x+y+2)/4 =0
(x+2y)/3 = (x+y+2)/4
4(x+2y) = 3(x+y+2)
4x+8y = 3x +3y +6
4x -3x = 3y -8y+6
x= -5y +6

=> Igualamos las "x" :

(-3y +1)/2 = -5y+6
-3y+1 = 2(-5y+6)
-3y+1 = -10y +12
-3y +10y =12 -1
7y= 11
y= 11/7

=> Hallamos "x" :

x= -5y +6
x= - 5(11/7) +6
x= -55/7 +6
x= -13/7

Espero te sirva !! ^^